Seymour, Iowa

Seymour is located in Wayne County. About 634 people live here (as of 2020). Between 2010 and 2020, the population declined from 701 to 634. The region is at 323 meters above sea level. The area covers about 6.1 square kilometers. There are about 58 streets in Seymour. The ZIP codes are 52590. Seymour is city in Iowa, United States. Among other things, Seymour has doctors.

Seymour – Facts

Population 634
Area 6.1 km²
Elevation 323 m
Located in Wayne County
Postal code 52590
Country United States
Official name Seymour

Data source: Wikidata (CC0)

Streets in Seymour, Iowa