Town of Beekmantown Township, New York

Town of Beekmantown is located in Clinton County. About 5,508 people live here. Between 2010 and 2020, the population declined from 5,545 to 5,508. The region is at 87 meters above sea level. There are about 188 streets in Town of Beekmantown. The dialing code is 518. Town of Beekmantown is human settlement in Clinton County, New York, United States of America.

Town of Beekmantown – Facts

Population 5508
Area 69.6
Elevation 87 m
Located in Clinton County
Country United States
Official name Town of Beekmantown

Data source: Wikidata (CC0)

Streets in Town of Beekmantown Township, New York